What would be the coordinates at 315° if the coordinates at 135° are at (-square root 2/2, square root 2/2)?

We choose C

Step-by-step explanation:

the coordinates at 135° are at  (, )

As we can see, the x coordinate of the point is negative and the y coordinate of it is positive.

So this point is located at the quadrant ii

From  135 ° to 315°, it is rotated 180°

=> Each coordinate (x,y) is changed to (-x,-y)

= (, )  the new coordinate is located in quadrant iii

We choose C

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for