The height and radius of a cone are multiplied by 5. What effect does this have on the surface area of the cone?

The effect is that the new surface area is 5 times bigger when the radius and height are each multiplied by 5.

Step-by-step explanation:

The formula for surface area of a cone is given by the expression;

S = πrL

Where;

r is radius

L is slant height.

Now, in a cone, we know that the radius, vertical height and slant height form a triangle.

Thus, if vertical height is represented by h, using Pythagoras theorem, we will get;

h² = r² + L²

So, L² = h² - r²

L = √(h² - r²)

So surface area of a cone would be;

S = πrL = πr(√(h² - r²))

Now, we are told that the height and radius of a cone are each multiplied by 5.

Thus; r = 5r and h = 5h

So,our surface area is now;

S_new = πr(√((5h)² - (5r)²))

S_new = πr(√((25h²) - (25r²)))

Collecting like terms, we have;

S_new = πr(√(25(h² - r²)))

S_new = 5πr(√(h² - r²))

Comparing our new surface area to the initial one gotten, it is clear that the new surface area is 5 times bigger when the radius and height are each multiplied by 5.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.