Locate root 10 on the number line

To locate √10 on number line follow the steps. let 3cm = 1 unit. 1] √10 = √3²+1². 2]draw a number line OC such that OA=AB=OC=1 unit. 3] draw a perpendicular line from C of 1 unit [as √10 = √3²+1² ] and name the point as C. 4] join O and C it will form a triangle.

Step-by-step explanation:

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

answer: what are the following choices