Carol wanted to see how the data would change if she did not include the outlier in her study. The results are shown in the table with the outlier crossed out.
Find each listed value.
Range =
Median =
Lower quartile and upper quartile =
Interquartile range =
Which value was affected the most?

the range was affected the most

Step-by-step explanation:

The biggest watch news is: 46

The smallest watch news is" 26

So the range of the data

26 ≤ range ≤ 46

So we will rearrange the list:

26 26 32 35 38 39 40 45 46

So the median is 38

As we know the lower quartile value is the median of the lower half of the data. The upper quartile value is the median of the upper half of the data.

So, the lower quartile is: (26+32)/2 = 29

the upper quartile is: (40+45)/2 = 47.5

The upper quartile - the lower quartile = 47.5 -29 = 18.5

If she does not cross the outlier, our data set is:

26 26 32 35 38 39 40 45 46 72

=> median : (38+39)/2 = 38.5

=> The upper quartile: 45

=> The lower quartile: 32

=> Interquartile range : 45 -32 = 13

=> the range (26 ≤ range ≤ 72)

So the range was affected the most

range= 20

median= 38

Lower quartile and upper quartile = 29 and 42.5

Interquartile range = 13.5

Which value was affected the most? range

Step-by-step explanation:

edgu 2020 i just did it hope this helps frens :3

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it