49w^2-4=0. Simplied fraction?

{-2/7, 2/7}

Step-by-step explanation:

Here you're being asked to solve the given equation 49w^2-4=0 for w with the hint that the solutions are fractions.

49w^2-4=0 is the product of the sum and difference of two squares:

(7w - 2)(7w + 2) = 0

Setting each factor equal to zero and solving for w, we get:

{-2/7, 2/7} as the solutions.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

think about it deeply and passionately about this property

i am sorry