Find the area of a sector of a circle whose radius is 7 cm and whose central angle is 45
degrees. Use pi = 3.14.

The area of a sector of a circle = 19.2325

Step-by-step explanation:

Explanation:-

Given θ be the measure of angle and radius of circle

The area of a sector of a circle (see diagram)

                                       

Given the radius of circle 'r' = 7cm and given angle θ = 45°

The area of a sector of a circle

                                     

  Use pi =3.14

                                     

                                      A = 19.2325

Final answer:-

The area of a sector of a circle = 19.2325

                                         

Where is the graph function?

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12