Line segment BA is tangent to the circle.

A circle is shown. Secant D B and tangent B A intersect at point B outside of the circle. Secant D B intersects the circle at point C. The length of A B is x, the length of B C is 55, and the length of C D is 120.

What is the length of line segment BA? Round to the nearest unit.

Hence the length of line segment BA as 98 units

Step-by-step explanation:

Given:

BA as tangent to circle ,DB as secant which intersect at point C at circle

Length BC= 55 and CD=120

To Find:

Length of line segment AB.

Solution:

This follows the relationship between tangent and secant  in circle terms as:

Consider as figure such that ,

AB as tangent , DB as secant C be point at circle

So secant total distance = DB=BC+CD =55+120=175

Using formula as ,

We have to find AB

Here BC=55 and CD=120

So nearest unit for length will be 98

Hence the length of line segment BA as 98 units

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.