3. The length of a rectangle is increasing at a rate of 3 cm=s and its width is increasing at arate of 9 cm=s. When the length is 7 cm and the width is 5 cm, how fast is the area of therectangle increasing?

The area of the rectangle is increasing at 78cm/sec

Step-by-step explanation:

Explanation:-

Given the length of a rectangle is increasing at a rate of 3 cm/s

Given the width of a rectangle is increasing at a rate of 9 cm/s

we know that the area of the rectangle

                         A = l × w  …(l)

Differentiating equation with respective to 't'

Given the length of the rectangle = 7 cm and

The width of the rectangle w = 5 cm

Final answer:-

The area of the rectangle is increasing at 78cm/sec

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !