A cake recipe calls for 550 grams of flour. About how many pounds of flour do you need? Use the conversion factors StartFraction 1 ounce Over 28.4 grams EndFraction and StartFraction 1 pound Over 16 ounces EndFraction .

The question is:

A cake recipe calls for 550 grams of flour. About how many pounds of flour do you need? Use the conversion factors (1 ounce)/(28.4 grams) and (1 pound)/(16 ounces).

About 1.2 pounds of flour is needed.

Step-by-step explanation:

Given that the cake recipe calls for 550 grams, we want to determine about how many pounds of flour we need.

This simply means we want to convert 550 grams to pounds.

First, we were given (1 ounce)/(28.4 grams)

This implies that

1/28.4 = x/550 (1)

Where x is 550 grams in ounce.

Solving (1)

28.4x = 550

=> x = 550/28.4

≈ 19.3662

That is 550 grams is equal to 19.3662 ounce

Next, we are given the ratio (1 pound)/(16 ounce). We then convert 19.3662 ounce to pound

Let y be 19.3662 ounce in pound

=> 1/16 = y/19.3662

16y = 19.3662

y = 19.3662/16

≈ 1.2

That is 19.3662 ounce is equal to 1.2 pounds.

Therefore, 550 grams is equal to 1.2 pounds, and it is the amount of flour needed.

a. -0.3 > -0.33

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.