Pls help I’m timed thanks

Picture 1: b

Picture 2: d

Picture 3: c

Step-by-step explanation:

Hi there,

For Picture 1, to solve for an inverse function, just simply solve for x. Since the closest you can get is arccos(πx)=2y+6, you just

solve for cosine as a function: cos(2y+6)=πx and solving for x:

x= (1/π)cos(2y+6)    but since variable choice is arbitrary, you can now redefine y and x:

y= (1/π)cos(2x+6)

For Picture 2, tanx is equivalent to sinx/cosx and cscx is just the reciprocal of sinx. So, it becomes:

We have already been giving the cosine value of 2, and its inverse is thus 1/2.  

For Picture 3, I would recommend revisiting polar coordinates.

Polar coordinates are in the form (r, θ).

  and  θ . Recognize there are two possible radii, depending on what side of the circle you start from!

thanks,

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

22 dimes and 9 nickels

step-by-step explanation: