Sum of cubes:

(a + b)(a2 – ab + b2) = a3 + b3

Difference of cubes:

(a – b)(a2 + ab + b2) = a3 – b3

Which products result in a sum or difference of cubes? Check all that apply.

(x - 1)(x² + x + 1) = x³ - 1³  and (x + 4)(x² - 4x + 16) = x³ + 4³

Step-by-step explanation:

complete question is: Check all that apply.

(x – 4)(x2 + 4x – 16)

(x – 1)(x2 – x + 1)

(x – 1)(x2 + x + 1)

(x + 1)( + x – 1)

(x + 4)(x2 – 4x + 16)

(x + 4)(x2 + 4x + 16)

SOLUTION:

Formulas for sum of cubes and difference of cubes are:

x³ +y³ = (x + y) (x²- xy + y²)

x³ - y³=(x - y)(x² + xy + y²)

So,

->(x - 1)(x² + x + 1) = x³ - 1³

The above statement yields the difference of cubes.

->(x + 4)(x² - 4x + 16) = x³ + 4³

The above statement yields the sum of cubes.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

step-by-step explanation: