Margo deposited $100 into a savings account earning 4.5% simple annual interest. At the end of each year, she adds $100 to her account. Fill in the table below to figure out how much money was in Margo's account at the end of 3 years.

                    principal     interest              total money in account

                                                                         at the end of year

Year one       $100             $4.5                              $104.5

year two        $200          $ 9 +$4.5                         $ 213.5

year three      $300          $ 9 +$4.5 + $13.5           $ 327

Step-by-step explanation:

Simple interest for any principal is given by

I = p* r* t/100

I = interest rate accrued on principle amount

p is the amount deposited

r is the rate of interest

t is the time period of saving

For year one

p = $100

r = 4.5%

t=1

I = 100*4.5*1/100 = 4.5

For year two $100 more is added to already existing $100 in account.

p = 100 +100 = $200

r = 4.5%

t=1

I = 200*4.5*1/100 = 9

For year two $100 more is added to already existing $200 in account after two years.

p = 100 +100 +100 = $300

r = 4.5%

t=1

I = 300*4.5*1/100 = 13.5

There fore total  money in Margo account is

$300 saving deposited by her

$4.5 + $9 + $13.5 = $27 (interest accrued in three time)

Formulating the results in tabular form

                     principal     interest    total money in account

                                                            at the end of year

Year one       100               4.5                      104.5

year two        200           9 +4.5                     213.5

year three      300           9 +4.5 + 13.5           327

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1