What is the missing constant term in the perfect square that starts with x^2-12xx 2 −12xx

We have been given an expression . We are asked to determine the missing term in the expression that will make the expression a perfect square.

To complete a square, we need to add the square of half of the coefficient of x.

We can see that coefficient of x is . To complete the square we need to find half of the square of .

Upon adding 36 to our expression, we will get:

We can see that our expression is now perfect square as we can rewrite is as:

Therefore, the missing constant term in the given perfect square would be 36.

36

Step-by-step explanation:

If you are doing khan academy, then this is the correct answer! :)

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder