If xy+6e^y = 6e, find the value of y\" at the point where x = 0.

Xy + 6e^y = 6e
taking first derivative : 
xy' + y + 6y(e^y)(y') = 0 
xy" + y' + y' + 6y'(e^y)(y') + 6yy(e^y)y' + 6y(e^y)y" = 0 

Put x = 0,
0 + 6e^y = 6e,
y = 1 
0 + 1 + 6(1)(y')e = 0,
Put y' = 0 
0 + 0 + 0 + 0 + 0 +6 ey" = 0,
y" = 0

Ac equals 35 cm long

21, i'm pretty sure it's right lol