An object is launched from the ground the objects height in feet can be described by the quadratic function HT equals 80t -16t^2, where t is the time in seconds, since object is launched when will the object hit the ground after his launch explain how you found your answer

The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

13.46

step-by-step explanation:

16.80 x .20 = 13.46