Find all polar coordinates of point p if p=1,-x/6

All polar coordinates of point P are; (1 , -x/6 + 2nn) and (-1, -x/6 + (2n+1)n)

Step-by-step explanation:

The polar coordinates can be represented as;

(r,Ф)= (r,Ф+2nn) or (r,Ф) =(-r,Ф+(2n+1)n)

Where n is any integer value.

From the question, we are given that; p=(1,-x/6)

Comparing it with P(r,Ф), then r = 1 and Ф = -x/6

The polar coordinates will now be;

P(r,Ф) = (r,Ф+2nn)  = (1 , -x/6 + 2nn)

Where; n is any positive integer and the value of r is positive.

While;

P(r,Ф) =(-r,Ф+(2n+1)n) = (-1, -x/6+(2n+1)n) and n is any positive integer and the value of r is negative.

Thus, all polar coordinates of point P are  (1 , -x/6 + 2nn) and (-1, -x/6 + (2n+1)n)

38.6°

step-by-step explanation:

resultant is 10 pound

smaller force = 8 pound

angle formed = tan⁻¹(

                        =tan⁻¹(

                          =tan⁻¹(0.8)

                        =38.6°