What is the area of the trapezoid? [A = 1/2(b1 + b2)h]
A) 1249.5 sq cm
B) 162.75 sq cm
C) 105 sq cm
D) 38.75 sq cm

We can see that b1 = 18, b2 = 24, and h = 5

So, we can just substitute these in.

A = 1/2(18 + 24)5

A = 1/2 * 42 * 5

A = 21 * 5

A = 105

So, the answer is C. 105 sq cm

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3