Suppose you flip a coin and spin a spinner that is divided into 8 equal regions. Of the 8 equal regions, 3 are red, 4 are black and 1 green. What is the probability of "tails" on the coin, and the spinner landing on red? (Hint: How many spaces are on the spinner total?)Immersive Reader
(5 Points)

18.75%

Step-by-step explanation:

The probability of the coin is 1/2, because it only has two options (tail or head).

Now, in the case of roulette, it has a total of 8 options, and the red region has 3 parts, that is, of the 8 options, roulette 3 is red, therefore the probability is 3/8

Now the final probability is the multiplication of the probability of both events:

(1/2) * (3/8) = 0.1875 s 18.75%

In other words, the probability of these two events happening, that the tail comes out and is red, i

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step-by-step explanation:

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