Un cultivo de bacterias se duplica cada hora. Si inicialmente, hay 1 bacteria, determina el numero de bacterias que se obtienen pasadas 3,4,6,7 y 12 hora

Hour 3

4 * 2 = 8

Hour 4

8 * 2 = 16

Hour 6

32 * 2 = 64

Hour 7

64 * 2 = 128

Hour 12

2048 * 2 = 4096

Step-by-step explanation:

We are told that initially there is a bacterium that doubles every hour, so let's calculate what happens in the first 12 hours every hour.

Hour 0

one

Hour 1

1 * 2 = 2

Hour 2

2 * 2 = 4

Hour 3

4 * 2 = 8

Hour 4

8 * 2 = 16

Hour 5

16 * 2 = 32

Hour 6

32 * 2 = 64

Hour 7

64 * 2 = 128

Hour 8

128 * 2 = 256

Hour 9

256 * 2 = 512

Hour 10

512 * 2 = 1024

Hour 11

1024 * 2 = 2048

Hour 12

2048 * 2 = 4096

We can deduce that the growth of the bacteria is:

2 ^ n

where n is the # of time that has passed

maybe i can

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15