A medical school claims that more than 28% of its students plan to go into general practice. It is found that among a random sample of 130 of the school's students, 32% of them plan to go into general practice. Find the P-value for a test of the school's claim.

a. 0.1635
b. 0.3461
c. 0.1539
d. 0.3078

And the best option would be:

c. 0.1539

Step-by-step explanation:

Data given and notation

n=130 represent the random sample taken

estimated proportion of students who plan to go into general practice

is the value that we want to test

z would represent the statistic (variable of interest)

represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.28:  

Null hypothesis:  

Alternative hypothesis:  

When we conduct a proportion test so we need to use the z statistic, and the is given by:  

(1)  

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

Statistical decision  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

And the best option would be:

c. 0.1539

unless if u could do my questions, if not i wouldn't want to

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.