Mathematics, 06.05.2020 02:10, rayanne6050

Location is knownLocation is known to affect the number, of a particular item, sold by an automobile dealer. Two different locations, A and B, are selected on an experimental basis. Location A was observed for 18 days and location B was observed for 13 days. The number of the particular items sold per day was recorded for each location. On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4. Does the data provide sufficient evidence to conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B at the 0.01 level of significance

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There is enough evidence to support the claim that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 0$

Being μ1: true mean number of sales for Location A and μ2: true mean number of sales for Location B.

The significance level is 0.01.

The sample 1 has a size n1=18 and the sample 2 has a size n2=13.

The sample 1 has a mean of 39 and a standard deviation of 8.

The sample 2 has a mean of 49 and a standard deviation of 4.

The difference between sample means is Md=-10.

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{8^2}{18}+\dfrac{4^2}{13}}\\\\\\s_{M_d}=\sqrt{3.556+1.231}=\sqrt{4.786}=2.188$

Then, we can calculate the t-statistic as:

The degrees of freedom for this test are:

This test is a left-tailed test, with 29 degrees of freedom and t=-4.571, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.00004) is smaller than the significance level (0.01), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

answered: Guest

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

answered: Guest

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.