Mathematics, 06.05.2020 03:23, kprincess16r

(Extra credit) All human blood can be typed as one of O, A, B, or AB. The distribution of the type varies a bit with race. For African-Americans, here are the approximate probabilities that a person will have blood type O, A, B, or AB. Blood Type O A B AB Probability 0.4 0.2 0.32 0.08 In a group of 10 randomly chosen people, what is the probability that two or more of them have Type A blood

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answered: tutyfruity29

Probability that two or more of them have Type A blood is 0.6242.

Step-by-step explanation:

We are given the approximate probabilities that a person will have blood type O, A, B, or AB.

Blood Type O A B AB

Probability 0.4 0.2 0.32 0.08

A group of 10 people are chosen randomly.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 10 people

r = number of success = two or more have Type A blood

p = probability of success which in our question is probability

that a person has Type A Blood, i.e; p = 20% or 0.20

LET X = Number of person having Type A Blood

So, it means X ~ Binom(n = 10, p = 0.20)

Now, Probability that two or more of them have Type A blood is given by = P(X $\geq$ 2)

P(X $\geq$ 2) = 1 - P(X = 0) - P(X = 1)

= $1- \binom{10}{0}\times 0.20^{0} \times (1-0.20)^{10-0}-\binom{10}{1}\times 0.20^{1} \times (1-0.20)^{10-1}$

= $1- 1 \times 1 \times 0.80^{10}-10 \times 0.20 \times 0.80^{9}$

= 0.6242

Hence, the probability that two or more of them have Type A blood is 0.6242.

answered: Guest

1 is c

2 is a

3 is a

step-by-step explanation:

answered: Guest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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(Extra credit) All human blood can be typed as one of O, A, B, or AB. The distribution of the type v...