Mathematics, 06.05.2020 04:20, RG1971

Find the equation of a parabola with a focus at (-2,-3) and a directrix at y=-5

a.) y=1/4(x+2)^2-8
b.) y=1/4(x-2)^2-4
c.) y=1/16(x+2)^2-4
d.) y=1/4(x+2)^2-4

Answers: 3

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Find the equation of a parabola with a focus at (-2,-3) and a directrix at y=-5 a.) y=1/4(x+2)^2-8 b.) y=1/4(x-2)^2-4 c.) y=1/16(x+2)^2-4 d.) y=1/4(x+2)^2-4

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Find the equation of a parabola with a focus at (-2,-3) and a directrix at y=-5

a.) y=1/4(x+2)^2-8
b.) y=1/4(x-2)^2-4
c.) y=1/16(x+2)^2-4
d.) y=1/4(x+2)^2-4