Please help
6q^2 + q=0

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (2•3q2) +  q  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  6q2 + q  =   q • (6q + 1)

Equation at the end of step  3  :

 q • (6q + 1)  = 0

Step  4  :

Theory - Roots of a product :

4.1    A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

4.2      Solve  :    q = 0

 Solution is  q = 0

the answer is here: : )

:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )