Factoring polynomial expressions(quadratic)

x^2-6x+5

x = 5 and x = 1 are the factors

Step-by-step explanation:

identify the a, b, and c values (a=1 b= -6 c=5)

plug them into the quadratic formula

x = -(-6) ± √(-6)² - 4(1)(5) / 2(1)

multiply -1 by -6 to get 6

x = 6 ± √(-6)² - 4(1)(5) / 2(1)

multiply -6 by -6 to get 36

x = 6 ± √36 - 4(1)(5) / 2(1)

multiply 4 by 1 to get 4

x = 6 ± √36 - 4(5) / 2(1)

multiply 4 by 5 to get 20

x = 6 ± √36 - 20 / 2(1)

subtract 36 by 20 to get 16

x = 6 ± √16 / 2(1)

take the square root of 16 to get 4

x = 6 ± 4 / 2(1)

multiply 2 by 1 to get 2

x = 6 ± 4 / 2

add 6 by 4 to get 10

x = 10 / 2

divide 10 by 2 to get 5 (now you know the first factor is x=5)

x = 5

subtract 6 by 4 to get 2

x = 2 / 2

divide 2 by 2 to get 1 (now you have found the final factor x=1)

you know know that the factors of x²- 6x + 5 are x = 5 and x = 1

it would be:

c.parallelogram.