A park ranger wanted to compare the length of largemouth bass in two different lakes in a park. He randomly pulled 20 largemouth bass from each lake and measured the length of each fish. The table shows the mean length and the mean absolute deviation (MAD) of the largemouth bass in each lake. Lake Mean (in.) MAD 1 16 2 2 22 2 Calculate the means-to-MAD ratio. Can the park ranger conclude that the largemouth bass in Lake 2 are generally longer than the ones in Lake 1? Select from the drop-down menus to correctly answer the question. The park ranger conclude that Lake 2 generally has longer largemouth bass because the distributions of lengths in the two lakes are .

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.