The longer leg of a right triangle is 3 ft longer than the shorter leg. The hypotenuse is 6 ft longer than the shorter leg. Find the side lengths of the triangle.

S = 9

L = 12

H = 15

Step-by-step explanation:

So this is a system of equations.  Fist, let's set up the legs.

L is longer, S is shorter and H is hypotenuse.

S = S

L = S + 3

H = S + 6

Now what equation relates all three sides of a right triangle.  Pythagorean is the most obvious so let's use that.

S^2 + L^2 = H^2

S^2 + (S + 3)^2 = (S+6)^2

S^2 + S^2 + 6S + 9 = S^2 + 12S + 36

S^2 - 6S - 27

I am going to use completing the square

(S - 3)^2 - 36 = 0

(S - 3)^2 = 36

S - 3 = +/-6

S = +/-6 + 3

S = -3 or 9

Measures can't be negative so we will use 9.  Plug it back into the original 3 equations.

S = 9

L = 9 + 3 = 12

H = 9 + 6 = 15

And the pythagorean theorem

9^2 + 12^2 = H^2

225 = H^2

15 = H

So it works.  

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?