A ball is thrown from the top of a building. It’s height s(t) in meters above the ground is given by the equation −10t 2 + 10t + 120, where t is given in seconds. (i) Find the velocity of the ball when immediately before it hits the ground. (ii) Find the average velocity of the ball between when it was thrown and when it hit the ground.

215.92 dollars is the answer

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

13.46

step-by-step explanation:

16.80 x .20 = 13.46

the square root of 16 is 4.

4*4 = 16