10 teams enter a soccer tournament. In the first round teams paired in 5 pairs to play with each other. How many different pairings are possible neither the order of the pairings nor the order of teams within each pairing matters?

There are 945 ways to make the pairings

Step-by-step explanation:

Lets pick a team. There are a total of 9 ways to select its pair. Now we have 8 teams remaining, note that the team we picked at the start doesnt matter because it will eventually be picked and the order doesnt matter. From the 8 teams remaining we select one of them and we pick a pair for it; we have 7 possibilities since we hace 7 teams remaining.

From the 6 teams remaining we take one of them and we select its partner, we now have 5 possibilities. From the 4 teams remaining we select one of them and pick 1 of the 3 teams remaining as its pair. Then, we pair the remaining teams.

This gives us a total of 9*7*5*3 = 945 ways to pair the teams.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.