4 chairs and 3 tables together cost ₨ . 2100 and 5 chairs and 2 tables cost Rs.1750. Find the cost of 1 chair and 1 table while solving by elimination method.

Cost of one chair  = Rs . 150

Cost of one table = Rs. 500

Step-by-step explanation:

Let number of chairs denote x and no of tables denote y

4x + 3y = 2100 (i)

5x +2y = 1750 (ii)

Multiply equation (i) by 2 and (ii) by (-3) and now y will be eliminated.

(i)*2        8x + 6y =  4200

(ii)*(-3)   -15x - 6y = - 5250    {Now, add}

               - 7x     = - 1050

x = -1050/-7

x = Rs. 150

Plug in the value of x inn equation (i)

4*150 + 3y = 2100

600 + 3y = 2100

3y = 2100 - 600

3y = 1500

y= 1500/3

y =Rs 500

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it