the question is attached in the image below

y = 3/2x-5/2

Step-by-step explanation:

We have two points so we can write the equation for the line. (-1,-4) and (3,2)

First we can find the slope by using

m= (y2-y1)/(x2-x1)

m = (2- -4)/(3 - -1)

   =(2+4)/(3+1)

   = 6/4

    = 3/2

Then put the slope into the slope intercept form of the equation

y= mx+b  where m is the slope and b is the y intercept

y = 3/2x+b

We will use the point (3,2) and substitute it into the equation to find b

2 = 3/2(3)+b

2 = 9/2 +b

Subtract 9/2 from each side

4/2 -9/2 = 9/2-9/2 +b

-5/2 = b

y = 3/2x-5/2

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!