The length of a room is 8 ft greater than it is width. If each dimension is
increased by 2 ft, the area will be increased by 60 sq. ft. Find the dimensions of
the rooms.

Answer

Let width be equal to 'x'

Length = x + 8

Old area = x(x+8)

Now, dimension increases

Length = (x+10)

width = x + 2

New area = (x+2)(x+10)

New area- old area = 60

((x+2)(x+10)) - ( x(x+8))= 60

4x + 20 = 60

4x = 40

x = 10 ft

Length of original room = 10+8 = 18 ft

Width of original room  = 10 ft.

Length of increased dimension = 18 +2 = 20 ft

Width of increased dimension = 10 +2 = 12 ft.

for the points

step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47