A single die is rolled twice. The 36 equally-likely outcomes are shown to the right. Find the probability of getting A second number that is less than the first number

The probability of getting A second number that is less than the first number is

Step-by-step explanation:

Step(i):-

Given a single die is rolled twice

In throwing a die , there are six exhaustive elementary  events

1 or 2 or 3 or 4 or 5 or 6.

The total number of exhaustive events = 6

Given data a single die is rolled two times = 6² = 36

The total number of exhaustive cases n(S) = 36

Step(ii):-

Let 'E' be the event of getting A second number that is less than the first number.

The required pairs are

{(6,1),(6,2),(6,3),(6,4),(6,5),(5,4),(5,3),(5,2),(5,1),(4,3)(4,2),(4,1),(3,2),(3,1),(2,1)}

The total number of favorable cases n(E) = 15

The required probability

Conclusion:-

The probability of getting A second number that is less than the first number is

s

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.