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Solve the system of linear inequalities

1) 3x+y ≤ -15

2x - y ≥ -10

x+2y ≥ -10

2) 4x+y ≥5

2x-3y ≤ -1

x+2y ≤ 10

1. The solution is the region above the line y = -x/2 - 5 and below the lines y = 2x + 10 and y = -3x - 15. (All bold)

2. The solution is the region below y = -x/2 + 5 and above the lines y = 2x/3 + 1/3 and y = -4x + 5. (All bold)

Step-by-step explanation:

1) 3x+y ≤ -15

y ≤ -3x - 15

2x - y ≥ -10

y ≤ 2x + 10

x+2y ≥ -10

y ≥ -x/2 - 5

The solution is the region above the line y = -x/2 - 5 and below the lines y = 2x + 10 and y = -3x - 15. (All bold)

2) 4x+y ≥5

y ≥ -4x + 5

2x-3y ≤ -1

3y ≥ 2x + 1

y ≥ 2x/3 + 1/3

x+2y ≤ 10

2y ≤ -x + 10

y ≤ -x/2 + 5

The solution is the region below y = -x/2 + 5 and above the lines y = 2x/3 + 1/3 and y = -4x + 5. (All bold)

step-by-step explanation:

try remembering the steps

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.