The graph of the equation LaTeX: x^2+y^2-20x+14y+28=0
x
2
+
y
2
−
20
x
+
14
y
+
28
=
0
is a circle. What is the radius of this circle?
Group of answer choices

radius = 11

Step-by-step explanation:

The equation of a circle in general form is

x² + y² + 2gx + 2fy + c = 0

with radius =

x² + y² - 20x + 14y + 28 = 0 ← is in general form

with 2g = - 20 ⇒ g = - 10

2f = 14 ⇒ f = 7 and c = 28, thus

radius = = = = 11

a 10 percent increase

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts