A company sells cereals in boxes which measure 10 cm by 25 cm by 35 cm.
They make a special edition box which is mathematically similar to the original box.

The volume of the special edition box is 15 120cm .
Work out the dimensions of this box.

V = 12cm×30cm×42cm

Step-by-step explanation:

Given the dimension of original box to be 10 cm by 25 cm by 35 cm.

Volume of the box = length × breath ×height

V = 10×25×35

V = 8150

If they make a special edition box which is mathematically similar to the original box, then we can generalise the volume of the original box by writing it in terms of a constant k

V = 10k×25k×35k...1

V = 8750k³ cm³

Given the Volume of the special edition box to be 15,120cm³ which bus similar to the volume of the original box, then

15,120 = 8750k³

k³ = 15,120/8750

k³ = 1.728

k = 1.728^1/3

k = 1.2

The dimension of the special edition box will be gotten by substituting k = 1.2 into eqn 1

V = 10(1.2)×25(1.2)×35(1.2)

V = 12cm×30cm×42cm

1 3 5

step-by-step explanation:

i took the test: )

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)