Write a rule for the function:

x -2, -1, 0, 1, 2
y 1/3, 1, 3, 9, 27

y = 3^(x + 1).

Step-by-step explanation:

Here the y values are increasing by a factor 3  and when x = 0 y = 3,

so  y =  (3)^1 when x = 0  - that is y = (3)^(0 + 1)  = 3.

So y = 3^(x + 1)  is the rule.

Check: when x = -2,  y = 3^(-2+1) = 3 ^-1 = 1/3.

When x = 1, y = 3(1+1) = 3^2 = 9.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

the answer is d

step-by-step explanation: