A trapezoid has base lengths of 12 centimeters and 13 centimeters. The other sides have lengths of 5 centimeters and 10 centimeters. A rectangle with side lengths of 2 centimeters and 5 centimeters is connected to the side with length 10 centimeters.
What is the area of the composite figure?

The area of the composite figure is 392.12.

Step-by-step explanation:

The area of the composite figure = area of trapezoid + area of rectangle

Area of trapezium = ( a +b)h

Where: a is the length of the first base, b the length of the second base and h is the height of the trapzium.

Applying Pythagoras theorem, the height, h, is;

h =

  =

h  = 2

Area of trapezium = ( a +b)h

                              = (13 + 12) × 2

                              = 156

                              = 382.12

Area of trapezium is 382.12

Area of rectangle = length × width

                             = 5 × 2

                             = 10

Area of rectangle = 10

Therefore,

area of the composite figure = 382.12 + 10

                                               = 392.12

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

the answer is d

hope this