The sum of two polynomials is -yz to the second power-3z to the second power-4y+4. If one of the polynomials is y-4yz to the second power-3, what is the other polynomial?

- 5yz^2 - 3z^2 - 5y + 7

Step-by-step explanation:

The polynomial is:

  ( 1 )

this polynomial is the result of the sum of two polynomials, one of them given by

    ( 2 )

if you find to know what is the other polynomial, you can take the difference between the polynomial (1) and (2). It is necessary to take the difference between simmilar terms, as follow:

 - yz^2 - 3z^2 - 4y + 4

- (4yz^2          + y   - 3  )

 - yz^2 - 3z^2 - 4y + 4

- 4yz^2           - y   + 3  

- 5yz^2 - 3z^2 - 5y + 7

hence the other polynomial is - 5yz^2 - 3z^2 - 5y + 7

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

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the domain of a function is the set of input values, x , for which a function is defined. the domain is shown in the left oval in the picture below. the function provides an output value, f(x) , for each member of the domain.