Find the value of x such that the data set has the given mean. 102, 122, 103, 111, 106, x; mean 112 This is my last question on my online test and if i fail this question i fail the whole test

128

Step-by-step explanation:

112 x 6 = 672

672 - 102 - 122 - 103 - 111 - 106 = 128

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get