Mathematics, 24.04.2020 22:13, lke123
How would you describe the relationship between the real zeros and x-intercepts of the function y=log4^(x-2)
A. When you set the function equal to zero, the solution is x = 6; therefore, the graph has an x-intercept at x = 6.
B. When you substitute x = 0 into the function there is no solution; therefore, the graph will not have any x-intercepts.
C. Since there is an asymptote at x = 2, the graph will not have an x-intercept; therefore, the function will have no real zeros.
D. When you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.
H E L P
Answers: 3
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How would you describe the relationship between the real zeros and x-intercepts of the function y=lo...
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