A ball is thrown into the air with an initial upward velocity of 48 feet/second. If height h in
feet after t seconds is given by the function h(t) = – 16t2 + 48t + 4.
a) What height will the ball be when 2 seconds has passed?

b) In how many seconds will the ball reach its maximum height?

c) What is the ball’s maximum height?

 after 2 seconds the ball would be 96 feet in the air

in 9 seconds will it reach its max height

max height=136ft

Step-by-step explanation:

could you provide figure.

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5