"A random sample of 125 registered voters in Phoenix is asked if they favor the use of Oxygenated fuels year-round to reduce air pollution and 86 voters responded positively. The city office claims that more than 65% of voters in Phoenix use oxygenated fuels. At 5% level of significance, to test that more than 65% of voters in Phoenix used oxygenated fuels, the suitable null and alternative hypotheses are"

The p value for this case is higher than the significance level provided so we don't have enough evidence to reject the null hypothesis and we can't conclude that the true proportion is higher than 0.65

Step-by-step explanation:

Data given and notation

n=125 represent the random sample taken

X=86 represent the voters who respond positively

estimated proportion of voters who respond positively

is the value that we want to test

represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

represent the p value (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.65, and the system of hypothesis are:  

Null hypothesis:  

Alternative hypothesis:  

The statistic is given by:

(1)  

Replacing we got:

Conclusion

The significance level provided .

Since is a right tailed test the p value would be:  

The p value for this case is higher than the significance level provided so we don't have enough evidence to reject the null hypothesis and we can't conclude that the true proportion is higher than 0.65

step-by-step explanation: