How do dis problem? 6.4n-10=4.4n+6

Simplifying

6.4n + -10 = 4.4n + 6

Reorder the terms:

-10 + 6.4n = 4.4n + 6

Reorder the terms:

-10 + 6.4n = 6 + 4.4n

Solving

-10 + 6.4n = 6 + 4.4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4.4n' to each side of the equation.

-10 + 6.4n + -4.4n = 6 + 4.4n + -4.4n

Combine like terms: 6.4n + -4.4n = 2n

-10 + 2n = 6 + 4.4n + -4.4n

Combine like terms: 4.4n + -4.4n = 0.0

-10 + 2n = 6 + 0.0

-10 + 2n = 6

Add '10' to each side of the equation.

-10 + 10 + 2n = 6 + 10

Combine like terms: -10 + 10 = 0

0 + 2n = 6 + 10

2n = 6 + 10

Combine like terms: 6 + 10 = 16

2n = 16

Divide each side by '2'.

n = 8

Simplifying

n = 8

-ur local skatergirl, Rin:)

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.