The concentrations of two chemicals A and B as functions of time are denoted by x and y respectively. Each alone decays at a rate proportional to its concentration. Put together, they also interact to form a third substance, at a rate proportional to the product of their concentrations. All this is expressed in the equations:

dx/dt = −2x−xy,

dy/dt = −3y−xy.

Note that (x, y)=(0,0) is the only equilibrium state (both concentrations must be positive or zero).

(a) Find an equation for y(x):
dy/dx =

(b) Solve your equation to obtain a relationship between x and y. Letting x(0)=5 and y(0)=10, give the relationship as an equation involving x and y:

(Your answer will be an equation involving x and y.)

Note that one implication of your relationship should be that if x and y are positive and very small (so that x is very much smaller than ln(x)), y2/x3 is roughly constant.

(c) Suppose that x=y. From your equation, what are x and y in this case?
x = y=

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

wfirfkfr/jjfi; jn; p/ojkfvlbvmkmgkgkkkgkkg

step-by-step explanation:

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation: