Lookover Lane divides two rows of houses. Each house on one side of the lane is directly
opposite a house on the other side of the lane. The houses are numbered consecutively 1, 2, 3,
and so on along one side. Once the end of that side of the lane is reached, the consecutive
numbering continues at the house on the other side of the street opposite house number 1. The
consecutive numbering continues along this second side until the last house is numbered. When
the residents of house number 37 look directly across the lane, they see the house numbered 84.
How many houses are on Lookover Lane?

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

h/o/e/s mad

step-by-step explanation:

si si si

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

i'm not really sure how to answer that

step-by-step explanation: