In ∆abc, if the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively, what are m < b and m m b = 89.68°, and m c = 37.19°

m b = 53.12°, and m c = 89.68°

m b = 89.68°, and m c = 53.13°

m b = 37.20°, and m c = 53.12°

m b = 53.13°, and m c = 37.19°

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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