A line has a slope of -2/3 and passes through the point (-3,8). What is the equation of the line?

Step-by-step explanation:

We'll use the standard equation y=mx+b to solve this problem. m is the slope of the line and b is the y intercept.

We know the slope, but we have to solve for the y intercept. To do this (I mean solve for 'b'), we need to know the slope, x value, and y value. We know the slope (-2/3), x= -3, and y=8. Let's plug this into y=mx+b and solve for b.

Let's plug all of this back into the first equation y=mx+b.

That's the answer to this problem.

I hope this helps.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)