Mathematics, 23.04.2020 22:35, rosetoheart2
A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on green is 1/12, on blue is 1/12. In simplest form, what is the probability of landing on orange?
Answers: 1
![=1-[\frac{2}{3}+\frac{2}{12}]\\\\=1-[\frac{2}{3}+\frac{1}{6}]\\\\=1-[\frac{2*2}{3*2}+\frac{1}{6}]\\\\=1-[\frac{4}{6}+\frac{1}{6}]\\\\=1-[\frac{4+1}{6}]\\\\=1-\frac{5}{6}\\\\=\frac{6}{6}-\frac{5}{6}\\\\=\frac{1}{6}](/tpl/images/0622/4639/0cd86.png)
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A spinner has red, green, blue, and orange sections. The probability of landing on red is 2/3, on gr...
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