The weights of 2-pound bags of Best Dog Food are approximately normally distributed with a given mean Mu and standard deviation Sigma. According to the Empirical Rule, what percentage of the bags will have weights within 3 standard deviations of the mean?

The required percentage would be 99.7%.

Step-by-step explanation:

Since we have given that

It is normally distributed.

mean =

Standard deviation =

Weight = 2 pounds bag

We need to find the percentage of the bags will have weights within 3 standard deviations of the mean.

So, it becomes :

As we know that  Approximately 99.7% data falls within 3 standard deviation of the mean.

Hence, the required percentage would be 99.7%.

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages